Angular momentum of electron in 3^rd stationary orbit of hydrogen atom is

Option 1 - <math> <mrow> <mfrac> <mrow> <mi>h</mi> </mrow> <mrow> <mi>π</mi> </mrow> </mfrac> </mrow> </math>

Option 2 - <math> <mrow> <mfrac> <mrow> <mn>3</mn> <mi>h</mi> </mrow> <mrow> <mn>2</mn> <mi>π</mi> </mrow> </mfrac> </mrow> </math>

Option 3 - <math> <mrow> <mfrac> <mrow> <mi>h</mi> </mrow> <mrow> <mn>2</mn> <mi>π</mi> </mrow> </mfrac> </mrow> </math>

Option 4 - <math> <mrow> <mfrac> <mrow> <mi>h</mi> </mrow> <mrow> <mn>3</mn> <mi>π</mi> </mrow> </mfrac> </mrow> </math>

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Vishal Baghel | Contributor-Level 10

4 months ago

Correct Option - 2

Detailed Solution:

Orbital angular momentum = $\frac{n h}{2 π}$ $\frac{}{}$

= $\frac{3 h}{2 π} (? n = 3)$

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Angular momentum of electron in 3rd stationary orbit of hydrogen atom is