Class 11th Laws of Motion Physics Physics Laws of Motion

For a given system find out $T_{1}'$ and $T_{2}'$ (forces exerted by the pulley on the support) respectively.

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mn>4</mn> <mroot> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> <mrow></mrow> </mroot> <mo>,</mo> <mi> </mi> <mi> </mi> <mn>6</mn> <mroot> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> <mrow></mrow> </mroot> </math> </span></p>

Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mn>72</mn> <mroot> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> <mrow></mrow> </mroot> <mo>,</mo> <mi> </mi> <mi> </mi> <mn>60</mn> <mroot> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> <mrow></mrow> </mroot> </math> </span></p>

Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mn>80</mn> <mroot> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> <mrow></mrow> </mroot> <mo>,</mo> <mi> </mi> <mi> </mi> <mn>36</mn> <mroot> <mrow> <mrow> <mn>3</mn> </mrow> </mrow> <mrow></mrow> </mroot> </math> </span></p>

Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mn>40</mn> <mroot> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> <mrow></mrow> </mroot> <mo>,</mo> <mi> </mi> <mi> </mi> <mn>3</mn> <mroot> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> <mrow></mrow> </mroot> </math> </span></p>

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Alok Kumar Singh | Contributor-Level 10

4 months ago

Correct Option - 2

Detailed Solution:

From F.B. Ds of

$9 k g \to 90 - T_{1} = 9 a \dots . (1)$

$6 k g \to T_{1} - T_{2} = 6 a \dots . . (2)$

$5 k g \to T_{2} - 50 = 5 a \dots . . (3)$

$(1) + (2) + (3)$

$40 = 20 a ? a = 2 m / s^{2}$

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