3.17. How would you explain the fact that the first ionization enthalpy of sodium is lower than that of magnesium but its second ionization enthalpy is higher than that of magnesium?

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    Answered by

    Payal Gupta | Contributor-Level 10

    5 months ago

    3.17. Electronic configuration of Na and Mg are

    Na = 1s2 2s2 2p6 3s1
    Mg = 1s2 2s2 2p6 3s2

    First electron in both cases has to be removed from 3s-orbital but the nuclear charge of Na (+ 11) is lower than that of Mg (+ 12) therefore first ionization energy of sodium is lower than that of magnesium.
    After the loss of first electron, the electronic configuration of

    Na+ = 1s2 2s2 2p6
    Mg+ = 1s2 2s2 2p6 3s1

    Here electron is to be removed from inert (neon) gas configuration which is very stable and hence removal of second electron from Na+ requires more energy in comparison to Mg.
    T

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