7.51 Justify the placement of O, S, Se, Te and Po in the same group of the periodic table in terms of electronic configuration, oxidation state and hydride formation.
7.51 Justify the placement of O, S, Se, Te and Po in the same group of the periodic table in terms of electronic configuration, oxidation state and hydride formation.
-
1 Answer
-
7.51
The elements of group 16 are collectively called chalcogens.
[i]. Elements of group 16 have six valence electrons each. The general electronic configuration of these elements is ns2 np4, where n varies from 2 to 6.
[ii]. Oxidation state: As these elements have six valence electrons [ns2np4], they should display an oxidation state of -2. However, only oxygen predominantly shows the oxidation state of -2 owing to its high Electronegativity. It also exhibits the oxidation state of -1 [H2O2], zero [O2], and +2 [OF2].
However, the stability of the -2 oxidation state decreases on moving down a group due to a decrease in the El
...more
Similar Questions for you
HClO4 is the most acidic compound.
Group number = 11 (Atomic number = 111)
Heavier element of p block do not from pπ− pπ bonds as their atomic orbital are so large and diffius that they cannot have effecitve overlapping.
The inertness of
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 688k Reviews
- 1800k Answers