Among the following pairs of orbitals, which orbital will experience more effective nuclear charge (i) 2s and 3s (ii) 4d and 4f (iii) 3d and 3p?
Among the following pairs of orbitals, which orbital will experience more effective nuclear charge (i) 2s and 3s (ii) 4d and 4f (iii) 3d and 3p?
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1 Answer
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Greater the penetration of the electron present in a particular orbital towards the nucleus more will be the magnitude of the effective nuclear charge. Based upon this
(i) 2s orbital is closer to the nucleus than 3s orbital and hence it will experience more effective nuclear charge.
(ii) 4d orbital will experience more effective nuclear charge due to its closer proximity to 4f orbital.
(iii) 3p orbital will experience more effective nuclear charge as it is closer to the nucleus
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Kindly go through the answers
(7.00)
Kindly consider the following Image
In 4d orbital, n = 4 and
Radial nodes =
Radial nodes = 4 – 2 – 1 = 1
And angular nodes,
Here, number of unpaired electrons, n = 1
Spin only moment ;
= 173 × 10-2 B.M
=
= (At constant pressure)
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