An inorganic compound 'X' on treatment with concentrated H2SO4 produces brown fumes and given dark brown ring with FeSO4 in presence of concentrated H2SO4. Also compound 'X' gives precipitate 'Y', when its solution in dilute HCl is treated with H2S gas. The precipitate ' Y', on treatment with concentrated HNO3 followed by excess of NH4OH further given deep blue coloured solution, Compound 'X' is:

Option 1 - <p>Cu(NO<sub>3</sub>)<sub>2</sub></p>
Option 2 - <p>Pb(NO<sub>3</sub>)<sub>2</sub></p>
Option 3 - <p>Co(NO<sub>3</sub>)<sub>2</sub></p>
Option 4 - <p>Pb(NO<sub>2</sub>)<sub>2</sub></p>
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6 months ago
Correct Option - 1
Detailed Solution:

X H 2 S O 4 C o n c Brown fumes + Brown ring test with FeSO4/H2SO4

x H C l H 2 S Y ( p p t ) H N O 3 C o n c d i s s o l v e d N H 4 O H Deep blue colour solution

In cation analysis of Cu+ ions, precipitate formed is CuS on treating with H2S and HCl which dissolved in HNO3 and produced blue colour complex solution [ C u ( N H 3 ) 4 ] + + in NH4OH. Brown fumes and brown ring performance given by nitrate

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Chemistry Ncert Solutions Class 12th 2023

Chemistry Ncert Solutions Class 12th 2023

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