An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1% more neutrons than the electrons, find the symbol of the ion.

3 Views|Posted 9 months ago
Asked by Shiksha User
1 Answer
A
9 months ago

Let the no. of electron in the ion = x
∴ The no. of protons = x – 1 (as the ion has one unit negative charge)
and the no. of neutrons = x +  (x*11.1 / 100) = 1.111 x
Mass of the ion = No. of protons + No. of neutrons
(x – 1) + (1.111 x)

Given mass of the ion = 37
∴ (x – 1) + (1.111 x) = 37

=> 2.111 x = 37

...Read more

Thumbs Up IconUpvote Thumbs Down Icon

Similar Questions for you

In 4d orbital, n = 4 and l=2

Radial nodes = nl1

Radial nodes = 4 – 2 – 1 = 1

And angular nodes,  l=2

B 2 + σ 1 s 2 s * 1 s 2 σ 2 s 2 σ * 2 s 2 π 2 p 1  

Here, number of unpaired electrons, n = 1

Spin only moment ;    μ = n ( n + 2 ) B . M

= 173 × 10-2 B.M

 

...Read more

Δ H = Δ U + Δ ( P V )

= Δ U + P Δ V + V Δ P

= Δ U + P Δ V   (At constant pressure)

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers

Learn more about...

Chemistry Ncert Solutions Class 11th 2023

Chemistry Ncert Solutions Class 11th 2023

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering