Ncert Solutions Chemistry Class 11th Chemistry Class 11th Structure of Atoms

An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1% more neutrons than the electrons, find the symbol of the ion.

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1 Answer

Answered by

alok kumar singh | Contributor-Level 10

3 months ago

Let the no. of electron in the ion = x
∴ The no. of protons = x – 1 (as the ion has one unit negative charge)
and the no. of neutrons = x + (x×11.1 / 100) = 1.111 x
Mass of the ion = No. of protons + No. of neutrons
(x – 1) + (1.111 x)

Given mass of the ion = 37
∴ (x – 1) + (1.111 x) = 37

=> 2.111 x = 37 + 1 = 38
x = 38 / 2.111 = 18
No. of electrons = 18; No. of protons = 18 – 1 = 17
Atomic no. of the ion = 17; atom corresponding to ion = Cl
Symbol of the ion = ³⁷₁₇Cl^–

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