Ask & Answer Question

Chemistry NCERT Exemplar Solutions Class 11th Chapter Four Molecular Orbital Theory Chemistry Chemical Bonding and Molecular Structure Chemistry Class 11th

Bonding in which of the following diatonic molecule(s) become(s) stronger, on the basis of MO Theory, by removal of an electron?

(A) NO

(B) N2

(C) O2

(D) C2

(E) B2

Choose the most appropriate answer from the options given below:

Option 1 -

(A), (B), (C) only

Option 2 -

(B), (C), (E) only

Option 3 -

(A), (C) only

Option 4 -

(D) only

2 Views | Posted 3 weeks ago

Asked by Shiksha User

1 Answer

Answered by

Raj Pandey | Contributor-Level 9

3 weeks ago

Correct Option - 3

Detailed Solution:

Bond strength $\propto$ Bond order

$N_{2} \to σ_{1 s}^{2} σ_{1 s}^{* 2} σ_{2 s}^{2} σ_{2 s}^{* 2} π_{2 p x}^{2} \equiv π_{2 p y}^{2} σ_{2 p z}^{2}$

$O_{2} \to σ_{1 s}^{2} σ_{1 s}^{* 2} σ_{2 s}^{2} σ_{2 s}^{* 2} σ_{2 p z}^{2} π_{2 p x}^{2} \equiv π_{2 p y}^{2} π_{2 p x}^{* 1} \equiv π_{2 p y}^{* 1}$

$C_{2} \to σ_{1 s}^{2} σ_{1 s}^{* 2} σ_{2 s}^{2} σ_{2 s}^{* 2} π_{2 p x}^{2} \equiv π_{2 p y}^{2}$

$B_{2} \to σ_{1 s}^{2} σ_{1 s}^{* 2} σ_{2 s}^{2} σ_{2 s}^{* 2} π_{2 p x}^{1} \equiv π_{2 p y}^{1}$

NO ® Number of electron = 7 + 8 = 15

B.O. Similar to $N_{2}^{-}$

$N_{2}^{-} \to σ_{1 s}^{2} σ_{1 s}^{* 2} σ_{2 s}^{2} σ_{2 s}^{* 2} π_{2 p x}^{2} \equiv π_{2 p y}^{2} σ_{2 p z}^{2} π_{2 p x}^{* 1} \equiv π_{2 p y}^{*}$

B.O. of N₂ = 3 B.O of C₂ = $\frac{8 - 4}{2} = 2$

Removal of e^- form antibonding molecular orbital increases bond order.

In NO & O₂ has valance e^- in p orbital.

Bond strength <math> <mrow> <mo>∝</mo> </mrow> </math>  Bond order <math> <mrow> <msub> <mrow> <mi>N</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <mo>→</mo> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>1</mn> <mi>s</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>1</mn> <mi>s</mi> </mrow> <mrow> <mo>*</mo> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>2</mn> <mi>s</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>2</mn> <mi>s</mi> </mrow> <mrow> <mo>*</mo> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>π</mi> </mrow> <mrow> <mn>2</mn> <mi>p</mi> <mi>x</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> <mo>≡</mo> <msubsup> <mrow> <mi>π</mi> </mrow> <mrow> <mn>2</mn> <mi>p</mi> <mi>y</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>2</mn> <mi>p</mi> <mi>z</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> </mrow> </math>   <math> <mrow> <msub> <mrow> <mi>O</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <mo>→</mo> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>1</mn> <mi>s</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>1</mn> <mi>s</mi> </mrow> <mrow> <mo>*</mo> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>2</mn> <mi>s</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>2</mn> <mi>s</mi> </mrow> <mrow> <mo>*</mo> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>2</mn> <mi>p</mi> <mi>z</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>π</mi> </mrow> <mrow> <mn>2</mn> <mi>p</mi> <mi>x</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> <mo>≡</mo> <msubsup> <mrow> <mi>π</mi> </mrow> <mrow> <mn>2</mn> <mi>p</mi> <mi>y</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>π</mi> </mrow> <mrow> <mn>2</mn> <mi>p</mi> <mi>x</mi> </mrow> <mrow> <mo>*</mo> <mn>1</mn> </mrow> </msubsup> <mo>≡</mo> <msubsup> <mrow> <mi>π</mi> </mrow> <mrow> <mn>2</mn> <mi>p</mi> <mi>y</mi> </mrow> <mrow> <mo>*</mo> <mn>1</mn> </mrow> </msubsup> </mrow> </math>  <math> <mrow> <msub> <mrow> <mi>C</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <mo>→</mo> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>1</mn> <mi>s</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>1</mn> <mi>s</mi> </mrow> <mrow> <mo>*</mo> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>2</mn> <mi>s</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>2</mn> <mi>s</mi> </mrow> <mrow> <mo>*</mo> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>π</mi> </mrow> <mrow> <mn>2</mn> <mi>p</mi> <mi>x</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> <mo>≡</mo> <msubsup> <mrow> <mi>π</mi> </mrow> <mrow> <mn>2</mn> <mi>p</mi> <mi>y</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> </mrow> </math>   <math> <mrow> <msub> <mrow> <mi>B</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <mo>→</mo> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>1</mn> <mi>s</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>1</mn> <mi>s</mi> </mrow> <mrow> <mo>*</mo> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>2</mn> <mi>s</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>2</mn> <mi>s</mi> </mrow> <mrow> <mo>*</mo> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>π</mi> </mrow> <mrow> <mn>2</mn> <mi>p</mi> <mi>x</mi> </mrow> <mrow> <mn>1</mn> </mrow> </msubsup> <mo>≡</mo> <msubsup> <mrow> <mi>π</mi> </mrow> <mrow> <mn>2</mn> <mi>p</mi> <mi>y</mi> </mrow> <mrow> <mn>1</mn> </mrow> </msubsup> </mrow> </math>  NO ® Number of electron = 7 + 8 = 15B.O. Similar to  <math> <mrow> <msubsup> <mrow> <mi>N</mi> </mrow> <mrow> <mn>2</mn> </mrow> <mrow> <mo>−</mo> </mrow> </msubsup> </mrow> </math>   <math> <mrow> <msubsup> <mrow> <mi>N</mi> </mrow> <mrow> <mn>2</mn> </mrow> <mrow> <mo>−</mo> </mrow> </msubsup> <mo>→</mo> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>1</mn> <mi>s</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>1</mn> <mi>s</mi> </mrow> <mrow> <mo>*</mo> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>2</mn> <mi>s</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>2</mn> <mi>s</mi> </mrow> <mrow> <mo>*</mo> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>π</mi> </mrow> <mrow> <mn>2</mn> <mi>p</mi> <mi>x</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> <mo>≡</mo> <msubsup> <mrow> <mi>π</mi> </mrow> <mrow> <mn>2</mn> <mi>p</mi> <mi>y</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>σ</mi> </mrow> <mrow> <mn>2</mn> <mi>p</mi> <mi>z</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>π</mi> </mrow> <mrow> <mn>2</mn> <mi>p</mi> <mi>x</mi> </mrow> <mrow> <mo>*</mo> <mn>1</mn> </mrow> </msubsup> <mo>≡</mo> <msubsup> <mrow> <mi>π</mi> </mrow> <mrow> <mn>2</mn> <mi>p</mi> <mi>y</mi> </mrow> <mrow> <mo>*</mo> </mrow> </msubsup> </mrow> </math>  B.O. of N2 = 3     B.O of C2 = <math> <mrow> <mfrac> <mrow> <mn>8</mn> <mo>−</mo> <mn>4</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> <mo>=</mo> <mn>2</mn> </mrow> </math>  Removal of e- form antibonding molecular orbital increases bond order.In NO & O2 has valance e- in p orbital.

0 Upvotes 0 Downvotes

Bonding in which of the following diatonic molecule(s) become(s) stronger, on the basis of MO Theory, by removal of an electron?

(A) NO

(B) N2

(C) O2

(D) C2

(E) B2

Choose the most appropriate answer from the options given below:

1 Answer

Similar Questions for you

Learn more about...

Most viewed information

Most viewed information

Share Your College Life Experience

Didn't find the answer you were looking for?

Need guidance on career and education? Ask our experts

Your Question

Bonding in which of the following diatonic molecule(s) become(s) stronger, on the basis of MO Theory, by removal of an electron? (A) NO (B) N2 (C) O2 (D) C2 (E) B2 Choose the most appropriate answer from the options given below:

1 Answer

Similar Questions for you

Learn more about...

Most viewed information

Most viewed information

Share Your College Life Experience

Didn't find the answer you were looking for?

Need guidance on career and education? Ask our experts

Your Question

Bonding in which of the following diatonic molecule(s) become(s) stronger, on the basis of MO Theory, by removal of an electron?

(A) NO

(B) N2

(C) O2

(D) C2

(E) B2

Choose the most appropriate answer from the options given below: