Calculate the energy required for the process: He+ (g) → He2+ (g) + e– The ionisation energy for the H atom in the ground state is 2.18 * 10-18 J atom-1

The expression for the ionization energy atom, En = (2.18 * 10-18 x Z2) / n2 J atom-1 For H atom, (Z = 1). So, En =2.18 * 10-18 * (l)2 J atom-1 (given) For He+ ion (Z = 2). So, En =2.18 * 10-18 * (2)2 = 8.72 * 10-18 J atom-1 (one electron species)

Calculate the energy required for the process:
He⁺ (g) → He²⁺(g) + e^–
**The ionisation energy for the H atom in the ground state is 2.18 * 10^-18J atom^-1**

16 Views|Posted 9 months ago

Asked by Shiksha User

1 Answer

Sort by:

Answered by

Alok Kumar Singh | Contributor-Level 10

9 months ago

The expression for the ionization energy atom,

E_n = (2.18 * 10^-18x Z²) / n²J atom^-1

For H atom, (Z = 1). So,

E_n =2.18 * 10^-18 * (l)² J atom^-1 (given)

For He⁺ ion (Z = 2). So,

E_n =2.18 * 10^-18 * (2)² = 8.72 * 10^-18 J atom^-1 (one electron species)

Upvote

Similar Questions for you

Find out the number of following orders which are INCORRECT against the mentioned properties:

(i) Ortho hydrogen > Para hydrogen (Stability at low temperature)

(ii) Ethanol > Glycerol (Viscosity)

(iii) D₂ < He (Boiling point)

(iv) HF > H₂O (Melting point)

(v) H₃BO₃ > BF₃ (Melting point)

(vi) NH₃ < SbH₃ (Boiling point)

(vii) H₂O₂ > H₂O (Strength of hydrogen bond)

(viii) H₂O < D₂O (Freezing point)

(ix) $H F_{2}^{Θ}$ < HF (Strength of hydrogen bond)

(x) D₂O < H₂O (Bond energy)

Vishal Baghel

Kindly go through the answers

(7.00)

Consider the following reaction:
(A substituted phenol reacts with H? and CrO?Cl to produce product 'P'.)
The product ‘P’ gives positive acetyl chloride test. This is because of the presence of which of these –OH group(s)?


Raj Pandey

Kindly consider the following Image

The number of radial land angular nodes in 4d orbital are, respectively

Payal Gupta

In 4d orbital, n = 4 and $l = 2$

Radial nodes = $n - l - 1$

Radial nodes = 4 – 2 – 1 = 1

And angular nodes, $l = 2$

The spin-only magnetic moment value of species is________× 10^-2 BM. (Nearest integer)

[Given:  $\sqrt[]{3} = 1.73]$

Alok Kumar Singh

$B_{2}^{+} \to σ 1 s^{2} s * 1 s^{2} σ 2 s^{2} σ * 2 s^{2} π 2 p^{1}$

Here, number of unpaired electrons, n = 1

Spin only moment ; $μ = \sqrt[]{n (n + 2)} B . M$

= 173 × 10^-2 B.M

Vishal Baghel

$Δ H = Δ U + Δ (P V)$

= $Δ U + P Δ V + V Δ P$

= $Δ U + P Δ V$ (At constant pressure)

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K

Colleges

1.2K

Exams

6.9L

Reviews

1.8M

Answers

Learn more about...

Chemistry Ncert Solutions Class 11th 2023

View Exam Details

52 Answered Questions

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

Ask Current Students, Alumni & our Experts

Quick Actions

Community GuidelinesUser Points System

QuestionsDiscussionsTags

Have a question related to your career & education?

See what others like you are asking & answering

Calculate the energy required for the process: He+ (g) → He2+ (g) + e–The ionisation energy for the H atom in the ground state is 2.18 * 10-18 J atom-1