Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise the sodium atom. Calculate the ionisation energy of sodium in kJ mol-1.

4 Views|Posted 9 months ago
Asked by Shiksha User
1 Answer
P
9 months ago

Given: λ = 242 nm = 142 x 10-9 m, c = 3 x 108 ms-1, h = 6.626 x 10-34Js

We know, E = hc / λ

= (6.626 * 10-34 Js) x (3 * 108 m s-1) / (242 * 10-9 m) = 0.0821 x 10-17 J

∴ Ionization energy per mol (E) = (0.0821 x 10-17 J) x (6.022 x 1023 mol-1J) / 1000 = 494 kJ mol-1

Thumbs Up IconUpvote Thumbs Down Icon

Similar Questions for you

In 4d orbital, n = 4 and l=2

Radial nodes = nl1

Radial nodes = 4 – 2 – 1 = 1

And angular nodes,  l=2

B 2 + σ 1 s 2 s * 1 s 2 σ 2 s 2 σ * 2 s 2 π 2 p 1  

Here, number of unpaired electrons, n = 1

Spin only moment ;    μ = n ( n + 2 ) B . M

= 173 × 10-2 B.M

 

...Read more

Δ H = Δ U + Δ ( P V )

= Δ U + P Δ V + V Δ P

= Δ U + P Δ V   (At constant pressure)

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers

Learn more about...

Chemistry Ncert Solutions Class 11th 2023

Chemistry Ncert Solutions Class 11th 2023

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering