Structure of Atoms Class 11th Chemistry Ncert Solutions Chemistry Class 11th

Emission transitions in the Paschen series end at orbit n = 3 and start from orbit n and can be represented as v = 3.29 x 10¹⁵ (Hz) [1/3² – 1 /n²]. Calculate the value of n if the transition is observed at 1285 nm. Find the region of the spectrum.

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Alok Kumar Singh | Contributor-Level 10

9 months ago

Given, ν = (3.29 x 10¹⁵ Hz) (1/3² – 1/n²)

= (3.29 x 10¹⁵ Hz) (1/3² – 1/n²)

(3 x 10⁸ ms^-1) / (1.285 x 10^-6 m) = (3.29 x 10¹⁵ Hz) (1/3² – 1/n²)

2.3346 x 10¹⁴ = (3.29 x 10¹⁵ Hz) (1/3² – 1/n²)

2.3346 / 32.9 = 1/3² – 1/n²

0.071 = 1/9 – 1/n²

1/n²= 1/9 – 0.071= 0.111 – 0.071 = 0.04

n²= 1/ 0.04 = 25

=> n = 5

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Chemistry Ncert Solutions Class 11th 2023

Chemistry Ncert Solutions Class 11th 2023

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