For the reaction : N2(g) + 3H2(g) ? 2NH3(g)
Equilibrium constant Kc =
Some reactions are written below in Column I and their equilibrium constants in terms of Kc are written in Column II. Match the following reactions with the corresponding equilibrium constant.
Column I (Reaction)
Column II (Equilibrium constant)
(i) 2N2(g) + 6H2(g) ⇌ 4NH3(g)
(a) 2Kc
(ii) 2NH3(g) ⇌N2(g) + 3H2(g)
(b) Kc
(iii) N2(g) + 2H2(g) ⇌ NH3(g)
(c)
(d) K2c
For the reaction : N2(g) + 3H2(g) ? 2NH3(g)
Equilibrium constant Kc =
Some reactions are written below in Column I and their equilibrium constants in terms of Kc are written in Column II. Match the following reactions with the corresponding equilibrium constant.
|
Column I (Reaction) |
Column II (Equilibrium constant) |
|
(i) 2N2(g) + 6H2(g) ⇌ 4NH3(g) |
(a) 2Kc |
|
(ii) 2NH3(g) ⇌N2(g) + 3H2(g) |
(b) Kc |
|
(iii) N2(g) + 2H2(g) ⇌ NH3(g) |
(c) |
|
|
(d) K2c |
This is a Matching Type Questions as classified in NCERT Exemplar
Ans: (i) → (d); (ii) → (c); (iii) → (b)
Similar Questions for you
0.01 M NaOH,
M = 1 * 10-2

pOH = 2
pH = 2
Kp = Kc (RT)Dng
36 * 10–2 = Kc (0.0821 * 300)–1
Kc = 0.36 * 0.0821 * 300 = 8.86 » 9
A(g) ->B(g) + (g)
Initial moles n 0 &nbs
On increasing pressure, equilibrium moves in that direction where number of gaseous moles decreases.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
Learn more about...

Chemistry NCERT Exemplar Solutions Class 11th Chapter Seven 2025
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
See what others like you are asking & answering

