Given below are two statements: one is labeled as Assertion A and the other is labeled as Reason R.

Assertion A: Flourine forms one oxoacid.

Reason R: Flourine has smallest size amongst all halogens and is highly electronegative.

In the light of the above statements, choose the most appropriate answer from the options given below.

$l^{-}+H_2{O}_2+2H^{+}\to l_2+2H_{2}O$

(-1) oxidation (0)

Here, I is reducing agent

${}_{}$ $\therefore H_2{O}_2$  behaves like oxidizing agent

In reducing action, H₂O₂ changes to O₂ because it will oxides but option (A) is in acidic medium, hence answer will be (C).

Urea acts as negative catalyst for decomposition of H₂O₂.

Tritium is radioactive and it decays into He³ during emission of β-radiation

₁T³ → ₂He³ + _-1e⁰

$CuO+H_2\to Cu+H_{2}O$