If the diameter of carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across a length of a scale of length 20 cm long.

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alok kumar singh | Contributor-Level 10

3 months ago

Length of scale = 20 cm = 20 x 10⁷ nm = 2 x 10⁸ nm

Diameter of carbon atom = 0.15 nm

∴ Number of carbon atoms which can be placed side by side in a straight line across a length of a scale of length 20 cm = (2 x 108 nm) / (0.15 nm) = 1.33 x 10⁹

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