If the equilibrium constant for <math> <mi>A</mi> <mo>⇌</mo> <mi>B</mi> <mo>+</mo> <mi>C</mi> </math> is <math> <msubsup> <mrow> <mrow> <mi>K</mi> </mrow> </mrow> <mrow> <mrow> <mo>(</mo> <mtext>eq</mtext> <mtext>&nbsp;</mtext> <mo>)</mo> </mrow> </mrow> <mrow> <mrow> <mo>(</mo> <mn>1</mn> <mo>)</mo> </mrow> </mrow> </msubsup> </math> and that of <math> <mi>B</mi> <mo>+</mo> <mi>C</mi> <mo>⇌</mo> <mi>P</mi> </math> is <math> <msubsup> <mrow> <mrow> <mi>K</mi> </mrow> </mrow> <mrow> <mrow> <mo>(</mo> <mtext>eq</mtext> <mtext>&nbsp;</mtext> <mo>)</mo> </mrow> </mrow> <mrow> <mrow> <mo>(</mo> <mn>2</mn> <mo>)</mo> </mrow> </mrow> </msubsup> </math> , the equilibrium constant for <math> <mi mathvariant="normal">A</mi> <mo>⇌</mo> <mi mathvariant="normal">P</mi> </math> &nbsp;is:

<math> <msubsup> <mrow> <mrow> <mi mathvariant="normal">K</mi> </mrow> </mrow> <mrow> <mrow> <mtext>(eq)</mtext> <mtext> </mtext> </mrow> </mrow> <mrow> <mrow> <mo>(</mo> <mn>2</mn> <mo>)</mo> </mrow> </mrow> </msubsup> <mo>-</mo> <msubsup> <mrow> <mrow> <mi mathvariant="normal">K</mi> </mrow> </mrow> <mrow> <mrow> <mtext>(eq)</mtext> <mtext> </mtext> </mrow> </mrow> <mrow> <mrow> <mo>(</mo> <mn>1</mn> <mo>)</mo> </mrow> </mrow> </msubsup> </math> (Equilibrium)

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Chemistry Class 12th Equilibrium Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven

If the equilibrium constant for $A ⇌ B + C$ is $K_{(eq)}^{(1)}$ and that of $B + C ⇌ P$ is $K_{(eq)}^{(2)}$ , the equilibrium constant for $A ⇌ P$ is:

Option 1 -

$K_{(eq)}^{(1)} K_{(eq)}^{(2)}$

Option 2 -

$K_{(eq)}^{(1)} / K_{(eq)}^{(1)}$

Option 3 -

$K_{(e q)}^{(1)} + K_{(e q)}^{(2)}$

Option 4 -

$K_{(eq)}^{(2)} - K_{(eq)}^{(1)}$ (Equilibrium)

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Answered by

alok kumar singh | Contributor-Level 10

3 months ago

Correct Option - 3

Detailed Solution:

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If the equilibrium constant for $A ⇌ B + C$ is $K_{(eq)}^{(1)}$ and that of $B + C ⇌ P$ is $K_{(eq)}^{(2)}$ , the equilibrium constant for $A ⇌ P$ is:

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If the equilibrium constant for A ⇌ B + C is K ( eq ) ( 1 ) and that of B + C ⇌ P is K ( eq ) ( 2 ) , the equilibrium constant for A ⇌ P is:

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If the equilibrium constant for $A ⇌ B + C$ is $K_{(eq)}^{(1)}$ and that of $B + C ⇌ P$ is $K_{(eq)}^{(2)}$ , the equilibrium constant for $A ⇌ P$ is: