Ionisation constant of a weak base MOH, is given by the expression
kb=
Values of ionisation constant of some weak bases at a particular temperature are given below:
Base
K b
Dimethylamine
5.4 * 10–4
Urea
1.3 * 10–14
Pyridine
1.77 * 10–9
Ammonia
1.77 * 10–5
Arrange the bases in decreasing order of the extent of their ionisation at equilibrium. Which of the above base is the strongest?
Ionisation constant of a weak base MOH, is given by the expression
kb=
Values of ionisation constant of some weak bases at a particular temperature are given below:
|
Base |
K b |
|
Dimethylamine |
5.4 * 10–4 |
|
Urea |
1.3 * 10–14 |
|
Pyridine |
1.77 * 10–9 |
|
Ammonia |
1.77 * 10–5 |
Arrange the bases in decreasing order of the extent of their ionisation at equilibrium. Which of the above base is the strongest?
This is a Short Answer Type Questions as classified in NCERT Exemplar
Ans: Higher the value of Kb stronger will be the base.
Kb- 5.4 * 10-4 >1.77 * 10-5 > 1.77 * 10-9> 1.3 * 10-14
Decreasing order of basic strength.
Dimethylamine > Ammonia > Pyridine > Urea
Hence among the given bases, the strongest b
Similar Questions for you
0.01 M NaOH,
M = 1 * 10-2

pOH = 2
pH = 2
Kp = Kc (RT)Dng
36 * 10–2 = Kc (0.0821 * 300)–1
Kc = 0.36 * 0.0821 * 300 = 8.86 » 9
A(g) ->B(g) + (g)
Initial moles n 0 &nbs
On increasing pressure, equilibrium moves in that direction where number of gaseous moles decreases.
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Chemistry NCERT Exemplar Solutions Class 11th Chapter Seven 2025
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