Ionisation constant of a weak base MOH, is given by the expression

kb= [ M + ] [ O H - ] [ M O H ]

Values of ionisation constant of some weak bases at a particular temperature are given below:

                        Base

                        K b

Dimethylamine

5.4 × 10–4

Urea

1.3 × 10–14

Pyridine

1.77 × 10–9

Ammonia

1.77 × 10–5

Arrange the bases in decreasing order of the extent of their ionisation at equilibrium. Which of the above base is the strongest?

0 1 View | Posted 4 months ago
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    Answered by

    Vishal Baghel | Contributor-Level 10

    4 months ago

    This is a Short Answer Type Questions as classified in NCERT Exemplar

    Ans: Higher the value of Kb stronger will be the base. 

    Kb-  5.4 * 10-4 >1.77 * 10-5 > 1.77 * 10-9> 1.3 * 10-14

    Decreasing order of basic strength. 

    Dimethylamine > Ammonia > Pyridine > Urea

    Hence among the given bases, the strongest base is Dimethylamine. 

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Kindly go through the solution

 

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