Ionisation constant of a weak base MOH, is given by the expression

kb= [ M + ] [ O H - ] [ M O H ]

Values of ionisation constant of some weak bases at a particular temperature are given below:

                        Base

                        K b

Dimethylamine

5.4 * 10–4

Urea

1.3 * 10–14

Pyridine

1.77 * 10–9

Ammonia

1.77 * 10–5

Arrange the bases in decreasing order of the extent of their ionisation at equilibrium. Which of the above base is the strongest?

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8 months ago

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: Higher the value of Kb stronger will be the base. 

Kb-  5.4 * 10-4 >1.77 * 10-5 > 1.77 * 10-9> 1.3 * 10-14

Decreasing order of basic strength. 

Dimethylamine > Ammonia > Pyridine > Urea

Hence among the given bases, the strongest b

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0.01 M NaOH,

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On increasing pressure, equilibrium moves in that direction where number of gaseous moles decreases.

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Chemistry NCERT Exemplar Solutions Class 11th Chapter Seven 2025

Chemistry NCERT Exemplar Solutions Class 11th Chapter Seven 2025

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