Match the species given in Column I with the hybridisation given in Column II. (i) Boron in [B(OH)4]− (a) sp2 (ii) Aluminium in [Al(H2O)6]3+ (b) sp3 (iii) Boron in B2H6 (c) sp3d2 (iv) Carbon in Buckminsterfullerene (v) Silicon in SiO44− (vi) Germanium in [GeCl6]2−

Match the species given in Column I with the hybridisation given in Column II.

(i) Boron in [B(OH)₄]⁻

(a) sp²

(ii) Aluminium in [Al(H₂O)₆]³⁺

(b) sp³

(iii) Boron in B₂H₆

(c) sp³d²

(iv) Carbon in Buckminsterfullerene

(v) Silicon in SiO₄⁴⁻

(vi) Germanium in [GeCl₆]²⁻

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Alok Kumar Singh | Contributor-Level 10

8 months ago

This is a Matching Type Questions as classified in NCERT Exemplar

(i)→ (b), (ii) → (c), (iii) → (b), (iv) → (a) (v)→ (b) (vi)→ (c)

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Chemistry NCERT Exemplar Solutions Class 11th Chapter Eleven 2025

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(i) Boron in [B(OH)₄]⁻	(a) sp²
(ii) Aluminium in [Al(H₂O)₆]³⁺	(b) sp³
(iii) Boron in B₂H₆	(c) sp³d²
(iv) Carbon in Buckminsterfullerene
(v) Silicon in SiO₄⁴⁻
(vi) Germanium in [GeCl₆]²⁻

Column I	Column II
(i) Diborane	(a) Used as a flux for soldering metals
(ii) Gallium	(b) Crystalline form of silica
(iii) Borax	(c) Banana bonds
(iv) Aluminosilicate	(d) Low melting, high boiling, useful for measuring high temperatures
(v) Quartz	(e) Used as catalyst in petrochemical industries.

Column I	Column II
(i) BF₄⁻	(a) Oxidation state of central atom is +4
(ii) AlCl₃	(b) Strong oxidising agent
(iii) SnO	(c) Lewis acid
(iv) PbO₂	(d) Can be further oxidised
	(e) Tetrahedral shape