Neon gas is generally used in sign boards. If it emits strongly at 616 nm, calculate:
(a) Frequency of emission (b) The distance travelled by this radiation in 30s (c) Energy of quantum (d) Number of quanta present if it produces 2 J of energy.

<p><strong> (a)</strong> Frequency of emission, ν = c/λ = (3.0 x 10⁸ ms^-1) / (616 x 10^-9 m) = 4.87 x 10¹⁴ s^-1</p><p><strong> (b)</strong> Speed of radiation, c = 3 x 10⁸ ms^-1</p><p>&nbsp;&nbsp;&nbsp;&nbsp; Distance travelled by this radiation in 30s = 3 x 10⁸ ms^-1x 30 s = 9.0 x 10⁹ m</p><p><strong> (c)</strong> Energy of quantum, E = hν =hc/λ = [ (6.626 x 10^-34Js) x (3 x 10⁸ ms^-1)] / (616 x 10^-9 m) = 32.27 x 10^-20J</p><p><strong> (d)</strong> Number of quanta present if it produces 2 J of energy</p><p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; = (Total energy) / (Energy per quanta) = 2J / (32.27 x 10^-20 J) = 6.2 x 10¹⁸</p>

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