P4O6 reacts with water according to equation P4O6 + 6H2O→ 4H3PO3. Calculate the volume of 0.1 M NaOH solution required to neutralise the acid formed by dissolving 1.1 g of P4O6 in H2O.
P4O6 reacts with water according to equation P4O6 + 6H2O→ 4H3PO3. Calculate the volume of 0.1 M NaOH solution required to neutralise the acid formed by dissolving 1.1 g of P4O6 in H2O.
This is a short answer type question as classified in NCERT Exemplar
P4O6 + 6H2O→4H3PO3 (i)
Next is neutralization
4 times H3PO3 + 2NaOH→Na2HPO3 + 2H2O (ii)
On addition of 2 equations
P4O6+8NaOH→4Na2HPO3+2H2O
P4O6 ( mol.mass )= (4*31+16*6)=220
Number of moles of P4O6 = =
The product formed is neutr
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Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven 2025
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