The arrangement of orbitals on the basis of energy is based upon their (n+l ) value. Lower the value of (n+l ), lower is the energy. For orbitals having same values of (n+l), the orbital with lower value of n will have lower energy.
The arrangement of orbitals on the basis of energy is based upon their (n+l ) value. Lower the value of (n+l ), lower is the energy. For orbitals having same values of (n+l), the orbital with lower value of n will have lower energy.
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1 Answer
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This is a Short Answer Type Questions as classified in NCERT Exemplar
Ans: Based upon the above information, arrange the following orbitals in the increasing order of energy.
(a) 1s, 2s, 3s, 2p
(b) 4s, 3s, 3p, 4d
(c) 5p, 4d, 5d, 4f, 6s
(d) 5f, 6d, 7s, 7p
Thus, the increasing order of energy is 3s<3p<4s<4d
Thus, the increasing order of energy is 4d<5p<6s<4f<5d
Thus, the increasing order of energy is 7s<5f<6d<7p
(II) Based upon the above information, solve the questions given below :
(a) Which of the following orbitals has the lowest energy?
4d, 4f, 5s, 5p
Ans -
The lowest
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Kindly go through the answers
(7.00)
Kindly consider the following Image
In 4d orbital, n = 4 and
Radial nodes =
Radial nodes = 4 – 2 – 1 = 1
And angular nodes,
Here, number of unpaired electrons, n = 1
Spin only moment ;
= 173 × 10-2 B.M
=
= (At constant pressure)
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