The diameter of zinc atom is 2.6 Å. Calculate
(a) The radius of zinc atom in pm
(b) Number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side length wise.

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Alok Kumar Singh | Contributor-Level 10

9 months ago

(a) The diameter of zinc atom is 2.6 Å =2.6*10⁻¹⁰m.

The radius of Zn atom is (2.6*10⁻¹⁰) / 2=1.3*10⁻¹⁰m=130*10⁻¹²m=130 pm.

(b) The number of Zn atoms present on 1.6 cm of length are 1.6 / (2.6*10⁻⁸) =6.154*10⁷.

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The diameter of zinc atom is 2.6 Å. Calculate (a) The radius of zinc atom in pm(b) Number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side length wise.