The diameter of zinc atom is 2.6 Å. Calculate (a) The radius of zinc atom in pm (b) Number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side length wise.

(a) The diameter of zinc atom is 2.6 Å =2.6×10−10m. The radius of Zn atom is (2.6×10−10) / 2=1.3×10−10m=130×10−12m=130 pm. (b) The number of Zn atoms present on 1.6 cm of length are 1.6 / (2.6×10−8) =6.154×107.

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Ncert Solutions Chemistry Class 11th Chemistry Class 11th Structure of Atoms

The diameter of zinc atom is 2.6 Å. Calculate
(a) The radius of zinc atom in pm
(b) Number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side length wise.

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alok kumar singh | Contributor-Level 10

3 months ago

(a) The diameter of zinc atom is 2.6 Å =2.6×10⁻¹⁰m.

The radius of Zn atom is (2.6×10⁻¹⁰) / 2=1.3×10⁻¹⁰m=130×10⁻¹²m=130 pm.

(b) The number of Zn atoms present on 1.6 cm of length are 1.6 / (2.6×10⁻⁸) =6.154×10⁷.

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The diameter of zinc atom is 2.6 Å. Calculate
(a) The radius of zinc atom in pm
(b) Number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side length wise.

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The diameter of zinc atom is 2.6 Å. Calculate (a) The radius of zinc atom in pm(b) Number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side length wise.

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The diameter of zinc atom is 2.6 Å. Calculate
(a) The radius of zinc atom in pm
(b) Number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side length wise.