The electronic energy in hydrogen atom is given by En = -2.18 × 10-18 / n2J. Calculate the energy required to remove an electron completely from the n = 2 orbit. What is the longest wavelength of light in cm that can be used to cause this transition?
The electronic energy in hydrogen atom is given by En = -2.18 × 10-18 / n2J. Calculate the energy required to remove an electron completely from the n = 2 orbit. What is the longest wavelength of light in cm that can be used to cause this transition?
-
1 Answer
-
Step I: Calculation of energy required
ΔE = E∞– E2
= 0 – (–2.18 × 10-18 J) / 4 = 5.45 x 10-19 J
Step II: Calculation of the longest wavelength of light in cm used to cause the transition
λ = hc / ΔE = (6.626 x 10-34 J s) x (3 x 108 ms-1) / (5.45 x 10-19 J)
= 3.644 x 10-7 x 102 = 3.645 x 10-5 cm.
Similar Questions for you
Kindly go through the answers
(7.00)
Kindly consider the following Image
In 4d orbital, n = 4 and
Radial nodes =
Radial nodes = 4 – 2 – 1 = 1
And angular nodes,
Here, number of unpaired electrons, n = 1
Spin only moment ;
= 173 × 10-2 B.M
=
= (At constant pressure)
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 687k Reviews
- 1800k Answers