The process that is NOT endothermic in nature is:
The process that is NOT endothermic in nature is:
Option 1 - <p><span class="mathml" contenteditable="false"> <math> <msub> <mrow> <mrow> <mi mathvariant="normal">H</mi> </mrow> </mrow> <mrow> <mrow> <mo>(</mo> <mi mathvariant="normal">g</mi> <mo>)</mo> </mrow> </mrow> </msub> <mo>+</mo> <msup> <mrow> <mrow> <mi mathvariant="normal">e</mi> </mrow> </mrow> <mrow> <mrow> <mo>-</mo> </mrow> </mrow> </msup> <mo>→</mo> <msubsup> <mrow> <mrow> <mi mathvariant="normal">H</mi> </mrow> </mrow> <mrow> <mrow> <mo>(</mo> <mi mathvariant="normal">g</mi> <mo>)</mo> </mrow> </mrow> <mrow> <mrow> <mo>-</mo> </mrow> </mrow> </msubsup> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <msubsup> <mrow> <mrow> <mi mathvariant="normal">O</mi> </mrow> </mrow> <mrow> <mrow> <mo>(</mo> <mi mathvariant="normal">g</mi> <mo>)</mo> </mrow> </mrow> <mrow> <mrow> <mo>-</mo> </mrow> </mrow> </msubsup> <mo>+</mo> <msup> <mrow> <mrow> <mi mathvariant="normal">e</mi> </mrow> </mrow> <mrow> <mrow> <mo>-</mo> </mrow> </mrow> </msup> <mo>→</mo> <msubsup> <mrow> <mrow> <mi mathvariant="normal">O</mi> </mrow> </mrow> <mrow> <mrow> <mo>(</mo> <mi mathvariant="normal">g</mi> <mo>)</mo> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> <mo>-</mo> </mrow> </mrow> </msubsup> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <msub> <mrow> <mrow> <mi mathvariant="normal">N</mi> <mi mathvariant="normal">a</mi> </mrow> </mrow> <mrow> <mrow> <mo>(</mo> <mi mathvariant="normal">g</mi> <mo>)</mo> </mrow> </mrow> </msub> <mo>→</mo> <msubsup> <mrow> <mrow> <mi mathvariant="normal">N</mi> <mi mathvariant="normal">a</mi> </mrow> </mrow> <mrow> <mrow> <mo>(</mo> <mi mathvariant="normal">g</mi> <mo>)</mo> </mrow> </mrow> <mrow> <mrow> <mo>+</mo> </mrow> </mrow> </msubsup> <mo>+</mo> <msup> <mrow> <mrow> <mi mathvariant="normal">e</mi> </mrow> </mrow> <mrow> <mrow> <mo>-</mo> </mrow> </mrow> </msup> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <msub> <mrow> <mrow> <mi mathvariant="normal">A</mi> <mi mathvariant="normal">r</mi> </mrow> </mrow> <mrow> <mrow> <mo>(</mo> <mi mathvariant="normal">g</mi> <mo>)</mo> </mrow> </mrow> </msub> <mo>+</mo> <msup> <mrow> <mrow> <mi mathvariant="normal">e</mi> </mrow> </mrow> <mrow> <mrow> <mo>-</mo> </mrow> </mrow> </msup> <mo>→</mo> <msubsup> <mrow> <mrow> <mi mathvariant="normal">A</mi> <mi mathvariant="normal">r</mi> </mrow> </mrow> <mrow> <mrow> <mo>(</mo> <mi mathvariant="normal">g</mi> <mo>)</mo> </mrow> </mrow> <mrow> <mrow> <mo>-</mo> </mrow> </mrow> </msubsup> </math> </span> (Thermodynamics)</p>
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7 months ago
Correct Option - 2
Detailed Solution:
Sol.
colourless
Oxidation state in is +3
Similar Questions for you
3CaO + 2Al → 3Ca + Al? O?
ΔH? = ΣΔH? (Products) - ΣΔH? (Reactants)
ΔH? = [ (0) + (-1675) ] - [ (3 × -635) + (0) ]
ΔH? = -1675 - (-1905) = -1675 + 1905 = 230 kJ
Ans = 230
Water has only two lone pair and XeF4 has two lone pair electron in opposite plane of the central atom.
85gm NH3 = 5 moles of NH3
Enthalpy change for 1 mol = 23.4 kJ
Then enthalpy change for 5 mol = 23.4 * 5 = 117 kJ
Number of moles of C =
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