What is the lowest value of n which allows 'g' orbital to exist?

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Payal Gupta | Contributor-Level 10

9 months ago

The lowest value of l where 'g' orbital can be present = 4

As for any value 'n' of principal quantum number, the Azimuthal quantum number (l) can have a value from zero to (n – 1).

∴ For l = 4, the minimum of n where 'g' orbital can be present = 4+1=5.

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