What is the maximum number of emission lines when the excited electron of a hydrogen atom in n = 6 drops to the ground state?
What is the maximum number of emission lines when the excited electron of a hydrogen atom in n = 6 drops to the ground state?
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1 Answer
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The maximum no. of emission lines = [n (n–1)] /2 = [6 (6–1)] / 2 =3 × 5 = 15
The transitions that take place are as follows:
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In 4d orbital, n = 4 and
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=
= (At constant pressure)
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