What is the maximum number of emission lines when the excited electron of a hydrogen atom in n = 6 drops to the ground state?
What is the maximum number of emission lines when the excited electron of a hydrogen atom in n = 6 drops to the ground state?
The maximum no. of emission lines = [n (n–1)] /2 = [6 (6–1)] / 2 =3 * 5 = 15
The transitions that take place are as follows:

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Kindly go through the answers
(7.00)
Kindly consider the following Image
In 4d orbital, n = 4 and
Radial nodes =
Radial nodes = 4 – 2 – 1 = 1
And angular nodes,
Here, number of unpaired electrons, n = 1
Spin only moment ;
= 173 × 10-2 B.M
=
= (At constant pressure)
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Chemistry Ncert Solutions Class 11th 2023
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