What is the number of photons of light with wavelength 4000 pm which provide 1 Joule of energy?

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Payal Gupta | Contributor-Level 10

9 months ago

Given: h = 6.626 * 10^-34 Js,

c = 3 * 10⁸ m s^-1,

λ = 4000 pm = 4000 * 10^-12 m = 4 * 10^-9 m

Energy of photon (E) = hc / λ

= (6.626 * 10^-34 Js) x (3 * 10⁸ m s^-1) / (4 * 10^-9 m) = 4.969 x 10^-17 J

i.e. 4.969 x 10^-17 J is the energy of 1 photon

Therefore, 1 J is the energy of photons = 1 / (4.969 x 10^-17) =

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