89. Assume that the chances of a patient having a heart attack is 40%. It is also assumed that a meditation and yoga course reduces the risk of heart attack by 30% and prescription of certain drug reduces its chances by 25%. At a time a patient can choose any one of the two options with equal probabilities. It is given that after going through one of the two options the patient selected at random suffers a heart attack. Find the probability that the patient followed a course of meditation and yoga.

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    Answered by

    alok kumar singh | Contributor-Level 10

    4 months ago

    89. A patient has options to have the treatment of yoga and meditation and that of prescription of drugs.

    Let these events be denoted by E1 and E2 i.e.,

    E1 = Treatment of yoga and meditation

    E2 = Treatment of prescription of certain drugs

    P (E1) = P (E2) = 1/2

    Let A denotes that a person has heart attack, then P (A) = 40% = 0.40

    Yoga and meditation reduces heart attack by 30.

     Inspite of getting yoga and meditation treatment heart risk is 70% of 0.40

    P (A|E1)  = 0.40 x 0.70 = 0.28

    Also, Drug prescription reduces the heart attack rick by 25%

    Even after adopting the drug prescription hear rick is 75% of 0.40

    P (A|E2)&

    ...more

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A
alok kumar singh

P (2 obtained on even numbered toss) = k (let)

P (2) = 1 6  

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= 5 6 × 1 6 1 ( 5 6 ) 2

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A
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If x = 0, y = 6, 7, 8, 9, 10

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A
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P (2W and 2B) = P (2B, 6W) × P (2W and 2B)

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A
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V
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ax2 + bx + c = 0

D = b2 – 4ac

D = 0

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