If the area of the triangle formed by the positive x-axis, the normal and the tangent to the circle (x - 2)2 + (y – 3)2 = 25 at the point (5, 7) is A, then 24A is equal to………………
If the area of the triangle formed by the positive x-axis, the normal and the tangent to the circle (x - 2)2 + (y – 3)2 = 25 at the point (5, 7) is A, then 24A is equal to………………
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1 Answer
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Equation of normal is 4x – 3y + 1 = 0
Equation of tangent is 3x + 4y – 43 = 0
Area of triangle =
Similar Questions for you
Eqn : y – 0 = tan45° (x – 9) Þ y = (x – 9)
Option (B) is correct
|r1 – r2| < c1c2 < r1 + r2
->
Now,
(y – 2) = m (x – 8)
⇒ x-intercept
⇒
⇒ y-intercept
⇒ (–8m + 2)
⇒ OA + OB =
->
->
->
->Minimum = 18
Kindly consider the following figure
According to question,
Equation of required line is
Obviously B (2, 2) satisfying condition (i)
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