The line passes through the centre of circle x2 + y2 – 16x – 4y = 0, it interacts with the positive coordinate axis at A & B. Then find the minimum value of OA + OB, where O is origin.
The line passes through the centre of circle x2 + y2 – 16x – 4y = 0, it interacts with the positive coordinate axis at A & B. Then find the minimum value of OA + OB, where O is origin.
Option 1 -
20
Option 2 -
18
Option 3 -
12
Option 4 -
24
-
1 Answer
-
Correct Option - 1
Detailed Solution:(y – 2) = m (x – 8)
⇒ x-intercept
⇒
⇒ y-intercept
⇒ (–8m + 2)
⇒ OA + OB =
->
->
->
->Minimum = 18
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Eqn : y – 0 = tan45° (x – 9) Þ y = (x – 9)
Option (B) is correct
|r1 – r2| < c1c2 < r1 + r2
->
Now,
Kindly consider the following figure
According to question,
Equation of required line is
Obviously B (2, 2) satisfying condition (i)
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