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Let A = {Z∈C:|z+1z−1|<1} and B = {z∈C:arg(z−1z+1)=2π3}. Then A∪B is

Option 1 -

a portion of a circle centered at (0,−13) that lies in the second and third quadrants only

Option 2 -

a portion of a circle centered at (0,−13) that lies in the second quadrant only

Option 3 -

an empty set

Option 4 -

a portion of a circle of radius 23 that lies in the third quadrant only

0 2 Views | Posted 2 months ago
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The mean of the numbers a, b, 8, 5, 10 is 6 and their variance is 6.8. If M is the mean deviation of the numbers about the mean, then 25 M is equal to
P
Payal Gupta

 x¯=6=a+b+8+5+105⇒a+b=7 …… (i)

and

σ2=a2+b2+82+52+1025−62=6.8

a2 + b2 = 25 ……. (ii)

From (i) and (ii) (a, b) = (3, 4) or (4, 3)

Now mean deviation about mean

M=15 (3+2+2+1+4)=125

25M = 60

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