Set A has m elements and Set B has n elements. If the total number of subsets of A is 112 more than the total number of subsets of B, then the value of m.n is [numerical
Set A has m elements and Set B has n elements. If the total number of subsets of A is 112 more than the total number of subsets of B, then the value of m.n is [numerical
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1 Answer
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2? -2? =112. m=7, n=4. mn=28.
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Similarly we get A19 =
=
So, b = 2
Hence b - a = 4
Given x + 2y – 3z = a
2x + 6y – 11z = b
x – 2y + 7z = c
Here
For infinite solution
20a – 8b – 4c = 0 Þ 5a = 2b + c
Sum of all elements of [Sum of natural number upto 100 which are neither divisible by 3 nor by 5]
= 10100 – 3366 – 2100 + 630
= 5264
Kindly go through the solution
B = (I – adjA)5
N =
N =
Now
-> a100 + a2 = 2
->a =
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