5.24 Figure 5.17 shows the position-time graph of a body of mass 0.04 kg. Suggest a suitable physical context for this motion. What is the time between two consecutive impulses received by the body ? What is the magnitude of each impulse?
This graph could be of a ball rebounding between two walls separated by a distance of 2 cm.
The ball rebounds every 2 secs between the walls with uniform velocity.
Velocity of rebounding = displacement / time = ( 2 )/2 = 0.01 m/s
Initial momentum = mu = 0.04 4 kgm/s
Final momentum = -mu = -4 kgm/s
Magnitude of Impulse = Initial momentum – final momentum = 8 kgm/s
The time between two consecutive impulses is 2 secs, so the ball receives an impulse every 2 seconds.
<p>This graph could be of a ball rebounding between two walls separated by a distance of 2 cm.</p><p>The ball rebounds every 2 secs between the walls with uniform velocity.</p><p>Velocity of rebounding = displacement / time = ( 2 <span title="Click to copy mathml"><math><mo>*</mo><msup><mrow><mrow><mn>10</mn></mrow></mrow><mrow><mrow><mo>-</mo><mn>2</mn></mrow></mrow></msup></math></span> )/2 = 0.01 m/s</p><p>Initial momentum = mu = 0.04 <span title="Click to copy mathml"><math><mo>*</mo><mn>0.01</mn><mo>=</mo></math></span> 4 <span title="Click to copy mathml"><math><mo>*</mo><msup><mrow><mrow><mn>10</mn></mrow></mrow><mrow><mrow><mo>-</mo><mn>4</mn></mrow></mrow></msup></math></span> kgm/s</p><p>Final momentum = -mu = -4 <span title="Click to copy mathml"><math><mo>*</mo><msup><mrow><mrow><mn>10</mn></mrow></mrow><mrow><mrow><mo>-</mo><mn>4</mn></mrow></mrow></msup></math></span> kgm/s</p><p>Magnitude of Impulse = Initial momentum – final momentum = 8 <span title="Click to copy mathml"><math><mo>*</mo><msup><mrow><mrow><mn>10</mn></mrow></mrow><mrow><mrow><mo>-</mo><mn>4</mn></mrow></mrow></msup></math></span> kgm/s</p><p>The time between two consecutive impulses is 2 secs, so the ball receives an impulse every 2 seconds.</p>
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