11.11 Light of wavelength 488 nm is produced by an argon laser which is used in the photoelectric effect. When light from this spectral line is incident on the emitter, the stopping (cut-off) potential of photoelectrons is 0.38 V. Find the work function of the material from which the emitter is made.

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    Payal Gupta | Contributor-Level 10

    4 months ago

    11.11 Wavelength of the light produced by Argon laser, λ = 488 nm = 488 ×10-9 m

    Stopping potential of the photoelectrons, V0 = 0.38 V = 0.381.6×10-19 eV

    Planck’s constant, h = 6.626 ×10-34 Js

    Charge of an electron, e = 1.6 ×10-19 C

    Speed of the light, c = 3 ×108 m/s

    From Einstein’s photoelectric effect, we have the relation involving the work function 0 of the material of the emitter as:

    eV0=hcλ-0

    0=hcλ-eV0 = 6.626×10-34×3×108488×10-9×1.6×10-19 - 1.6 ×10-19×0.381.6×10-19 = 2.54 – 0.38 = 2.165 eV

    Therefore,, the material with which the emitter is made has the work function of 2.165 eV.

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