11.17 (a) For what kinetic energy of a neutron will the associated de Broglie wavelength be 1.40 * 10–10 m?

(b) Also find the de Broglie wavelength of a neutron, in thermal equilibrium with matter, having an average kinetic energy of (3/2) k T at 300 K.

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8 months ago

11.17 De Broglie wavelength of the neutron, λ = 1.40 *10-10 m

Mass of neutron, m = 1.66 *10-27 kg

Planck's constant, h = 6.626 *10-34 Js

Kinetic energy, Ek = 12mv2 …………..(1)

De Broglie wavelength and velocity (v) are related as

λ=hmv ……………..(2)

Combining equation (1) and (2), we get

Ek = 12m(hmλ)2 = h22mλ2 = (6.626*10-34)22*1.66*10-27*(1.40*10-10)2 = 6.75 *10-21 J = 6.75*10-211.6*10-19 eV = 42.17 *10-3eV

Temperature of the n

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This is a Short Answer Type Questions as classified in NCERT Exemplar

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Physics Ncert Solutions Class 12th 2023

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