11.19 What is the de Broglie wavelength of a nitrogen molecule in air at 300 K? Assume that the molecule is moving with the root-mean square speed of molecules at this temperature. (Atomic mass of nitrogen = 14.0076 u)

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    Payal Gupta | Contributor-Level 10

    4 months ago

    11.19 Temperature of the Nitrogen molecule, T = 300 K

    Atomic mass of nitrogen = 14.0076 u

    Hence, mass of Nitrogen molecule, m = 2 × 14.0076 u = 28.0152 u

    We know, 1 u = 1.66 ×10-27 kg

    So, m = 28.0152 × 1.66 ×10-27 kg = 4.65 ×10-26 kg

    Planck’s constant, h = 6.626 ×10-34 Js

    Boltzmann constant, k = 1.38 ×10-23 kg m2s-2K-1

    We have the expression that relates to mean kinetic energy ( 32kT) of the nitrogen molecule with root mean square speed ( vrms ) as:

    12mvrms2 = 32kT

    vrms=3kTm = 3×1.38×10-23×3004.65×10-26 = 516.814 m/s

    De Broglie wavelength of the nitrogen molecule

    λ=hmvrms = 6.626×10-344.65×10-26×516.814 = 2.76 ×10-11 m = 0.0276 nm

    Ther

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