11.23 (a) An X-ray tube produces a continuous spectrum of radiation with its short wavelength end at 0.45 Å. What is the maximum energy of a photon in the radiation?

(b) From your answer to (a), guess what order of accelerating voltage (for electrons) is required in such a tube?

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    Answered by

    Payal Gupta | Contributor-Level 10

    4 months ago

    11.23 Wavelength produced by X-ray, λ= 0.45 Å = 0.45 ×10-10 m

    Planck’s constant, h = 6.626 ×10-34 Js

    Speed of light, c = 3 ×108 m/s

    The maximum energy of a photon is given as:

    E = hcλ = 6.626×10-34×3×1080.45×10-10 = 4.417 ×10-15 J = 4.417×10-151.6×1019 eV = 27.6 ×103 eV = 27.6 keV

    Therefore, the maximum energy of an X-ray photon is 27.6 keV

    To get an X-ray of 27.6 keV, the incident electrons must possess at least 27.6 keV of kinetic energy. Hence an accelerating voltage in the order of 30 keV will be required.

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