13.13 The radionuclide decays according to =20.3 min. The maximum energy of the emitted positron is 0.960 MeV. Given the mass values: m ( = 11.011434 u and m ( ) = 11.009305 u, calculate Q and compare it with the maximum energy of the positron emitted.
13.13 The radionuclide decays according to =20.3 min. The maximum energy of the emitted positron is 0.960 MeV. Given the mass values: m ( = 11.011434 u and m ( ) = 11.009305 u, calculate Q and compare it with the maximum energy of the positron emitted.
13.13 The given values are
m ( = 11.011434 u and m ( ) = 11.009305 u
The given nuclear reaction:
Half life of nuclei, =20.3 min
The maximum energy possessed by the emitted positron = 0.960 MeV
The change in the Q-value (ΔQ) of the nuclear masses of the
ΔQ =
where
= Mass of an electron or positron = 0
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Physics Ncert Solutions Class 12th 2023
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