13.15 The Q value of a nuclear reaction A + b  C + d is defined by

Q = [ mA+mb – mC – md ] c2

where the masses refer to the respective nuclei. Determine from the given data the Q-value of the following reactions and state whether the reactions are exothermic or endothermic.

(i) H11 + H13  H12 + H12

(ii) C612 + C612  Ne1020 + He24

Atomic masses are given to be

m ( H12 ) = 2.014102 u

m ( H13 ) = 3.016049 u

m ( C612 ) = 12.000000 u

m ( Ne1020 ) = 19.992439 u

11 Views|Posted 7 months ago
Asked by Shiksha User
1 Answer
P
7 months ago

13.15 The given nuclear reaction is

H11 + H13  H12 + H12

Atomic mass

m ( H11 ) = 1.007825 u

m ( H12 ) = 2.014102 u

m ( H13 ) = 3.016049 u

The Q-value of the reaction can be written as:

Q = mH11+mH13-2m(H12)c2

1.007825+3.016049-2*2.014102c2

= (-4.33 *10-3 ) c2

But 1 u = 931.5 MeV/ c2

Q = -4.0334 MeV

The negative Q-value of the reaction shows that the reaction is endothermic.

The given nuc

...Read more

Thumbs Up IconUpvote Thumbs Down Icon

Similar Questions for you

A = A 0 e λ t 1     [Radio active decay law]

A 5 = A 0 e λ ( t 2 t 1 )

A v e r a g e l i f e = 1 λ = ( t 2 t 1 ) l n 5  

          

...Read more

f o r A , t 1 2 = 4 s e c  

= m A 0 e 0 . 6 9 3 4 × 1 6

m A = m A 0 e 4 × 0 . 6 9 3    -(1)

for B,

for B,  t 1 2 = 8 s e c  

m B = m B 0 e 2 × 0 . 6 9 3               -(2)

m A m B = m A O m B O e 4 × 0 . 6 9 3 e 2 × 0 . 6 9 3

m A m B = 2 5 1 0 0 = x 1 0 0 x = 2 5

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers

Learn more about...

Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering