13.23 In a periodic table the average atomic mass of magnesium is given as 24.312 u. The average value is based on their relative natural abundance on earth. The three isotopes and their masses are
(23.98504u),
(24.98584u) and (25.98259u). The natural abundance of is 78.99% by mass. Calculate the abundances of other two isotopes.
13.23 In a periodic table the average atomic mass of magnesium is given as 24.312 u. The average value is based on their relative natural abundance on earth. The three isotopes and their masses are
(23.98504u),
(24.98584u) and (25.98259u). The natural abundance of is 78.99% by mass. Calculate the abundances of other two isotopes.
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1 Answer
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13.23 Average atomic mass of magnesium, m = 24.312 u
Mass of magnesium isotope ,= 23.98504u
Mass of magnesium isotope
,M g 12 25 = 24.98584um 2 Mass of magnesium isotope
,M g 12 26 = 25.98259um 3 Let the abundance of magnesium isotope
beM g 12 24 = 78.99 %η 1 Let the abundance of magnesium isotope
beM g 12 25 = x %η 2 Therefore, the abundance of magnesium isotope
beM g 12 26 = (100 - 78.99 - x) %η 3 = (21.01 – x)%
The average atomic mass can be expressed as:
m =
=m 1 η 1 + m 2 η 2 + m 3 η 3 η 1 + η 2 + η 3 =23.98504 × 78.99 + 24.98584 x + 25.98259 ( 21.01 - x ) 100 =1894.578 + 24.98584 x + 545.894 - 25.98259 x 100 2440.472 - 0.99675 x 100 24.312 =
2440.472 - 0.99675 x 100 x = 9.3%
Therefore the abundance of
M g 12 25 is (21.01 – 9.3)11.71%M g 12 26
Similar Questions for you
Q = [4 *4.0026 – 15.9994] *931.5 MeV
Q = 10.2 MeV
for B,
for B,
The reaction is X²? → Y¹²? + Z¹²?
Binding energies per nucleon are: X=7.6 MeV, Y=8.5 MeV, Z=8.5 MeV.
Gain in binding energy (Q) = (Binding energy of products) - (Binding energy of reactants)
Q = (120 × 8.5 + 120 × 8.5) - (240 × 7.6) MeV
Q = (2 × 120 × 8.5) - (240 × 7.6) MeV = 2040 - 1824 = 216 MeV.
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