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14.7 A p-n photodiode is fabricated from a semiconductor with band gap of 2.8 eV. Can it detect a wavelength of 6000 nm?

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    Answered by

    Payal Gupta | Contributor-Level 10

    4 months ago

    14.7 Energy band gap of the given photodiode, Eg = 2.8 eV

    Wavelength, λ = 6000 nm = 6000 ×10-9 m

    The energy of a signal is given by the relation,

    E = hcλ

    Where

    h = Planck’s constant = 6.626 ×10-34 Js

    c = sped of light = 3 ×108 m/s

    E = 6.626×10-34×3×1086000×10-9 = 3.313 ×10-20 J = 3.313×10-201.6×10-19 eV = 0.207 eV

    Therefore the energy of a signal of wavelength 6000 nm is 0.207 eV, which is less than 2.8 eV – the energy band gap of the photodiode. Hence, the photodiode cannot detect the signal.

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