14.8 The number of silicon atoms per m3 is 5 × 1028. This is doped simultaneously with 5 × 1022 atoms per m3 of Arsenic and 5 × 1020 per m3 atoms of Indium. Calculate the number of electrons and holes. Given that ni = 1.5 × 1016 m–3. Is the material n type or p type?

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    Payal Gupta | Contributor-Level 10

    4 months ago

    14.8 Number of silicone atoms, nS = 5 *1028 / m3

    Number of arsenic atoms, nA = 5 *1022 / m3

    Number of indium atoms, nI = 5 *1020 / m3

    Number of thermally generated atoms, ni = 1.5 *1016 / m3

    Hence number of electrons, ne = 5 *1022- 1.5 *1016 = 4.99 *1022

    Number of holes = nH

    In thermal equilibrium, the concentration of electrons and holes in a semiconductor are related as:

    nenH = ni2

    Therefore, nH = ni2ne = (1.5*1016)24.99*1022 = 4.51 *109

    Since the number of electrons are more (4.99 *1022) than the number of holes (4.51 *109) , the material is a

    ...more

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