2.22 Just as precise measurements are necessary in science, it is equally important to be able to make rough estimates of quantities using rudimentary ideas and common observations. Think of ways by which you can estimate the following (where an estimate is difficult to obtain, try to get an upper bound on the quantity):
(a) The total mass of rain-bearing clouds over India during the Monsoon
(b) The mass of an elephant
(c) The wind speed during a storm
(d) The number of strands of hair on your head
(e) The number of air molecules in your classroom
2.22 Just as precise measurements are necessary in science, it is equally important to be able to make rough estimates of quantities using rudimentary ideas and common observations. Think of ways by which you can estimate the following (where an estimate is difficult to obtain, try to get an upper bound on the quantity):
(a) The total mass of rain-bearing clouds over India during the Monsoon
(b) The mass of an elephant
(c) The wind speed during a storm
(d) The number of strands of hair on your head
(e) The number of air molecules in your classroom
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1 Answer
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2.22
(a) During monsoons, a metrologist records about 215 cm of rainfall in India. So
Height of water column, h = 215 cm = 2.15 m
Area of the country, A = 3.3
Hence, volume of rain water, V = A = 7.09
Density of water,p = 1 kg/
Hence, mass of rain water = p
= 7.09 kgHence, the total mass of rain-bearing clouds over India is approximately 7.09 kg
(b) Consider a ship of known base area floating in the sea.
Let the depth of the ship be
Volume of water displaced by the ship, = A
Now, move an elephant on the ship and let the depth of the ship be&nbs
...more
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According to question, we can write
Total moles of gas = n = nOxygen + nOxygen =
Volume of gas = 12 × 22.4 litre = 268.8 litre = 2.688 × 105 cm3
Viscosity = Pascal . Second
=
= x = 1, x + 2y = -1, -x + z = 1
y = -1, Z = 0
Viscosity = [P1A-1T0]
1 msD = 1mm
10 vsD = 9msD
1vsD = 0.9 MsD
L.C. = 1MSD – 1VSD = 1 – 0.9 = 0.1 mm
Zero error = 4LC = 0.4 mm
Reading = MSR + VSR + correction
= 4.1 cm + 6 * .01 cm + (-0.04 cm) = (4.1 + 0.06 – 0.04) cm
= 4.12 cm = 412 * 10-2 cm
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