3.12 A ball is dropped from a height of 90 m on a floor. At each collision with the floor, the ball loses one tenth of its speed. Plot the speed-time graph of its motion between t = 0 to 12 s.
3.12 A ball is dropped from a height of 90 m on a floor. At each collision with the floor, the ball loses one tenth of its speed. Plot the speed-time graph of its motion between t = 0 to 12 s.
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1 Answer
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Given data:
Initial height, h = 90 m
Acceleration due to gravity, g = 9.8 ms2
Speed lost at each collision = 1/10 of its speed
time interval to be considered: 0 to 12 secs.
Step 1: Time to fall from 90 m
h = ½ gt2 ⇒ 90 = 21 × 9.8 × t2 ⇒ t2 = 9.8180 ≈ 18.37 ⇒ t ≈ 4.29 seconds
Step 2: Speed before first impact
v = gt = 9.8 × 4.29 ≈ 42 m/s
After hitting the floor with 42 m/s, ball rebound with;
vrebound = 0.9×42 = 37.8m/s
Step 3:
Max height after rebound:
Use: 
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Please find the solution below:
[h] = ML2T-1
[E] = ML2T-2
[V] = ML2T-2C-1
[P] = MLT-1
According to question, we can write
10 =
Average speed
(d) Initial velocity
Final velocity
Change in velocity
Momentum gain is along
Force experienced is along
Force experienced is in North-East direction.
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