3.23 A three-wheeler starts from rest, accelerates uniformly with 1 m s–2 on a straight road for 10 s, and then moves with uniform velocity. Plot the distance covered by the vehicle during the nth second (n = 1,2,3….) versus n. What do you expect this plot to be during accelerated motion: a straight line or a parabola?

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8 months ago

3.23 The distance covered by the 3 wheeler on a straight line in the nth second can be expressed as:

Sn = u + a (2n-1)/2 …… (1),

Where

a = acceleration

u = initial velocity

n = time = 1,2,3, ……., n

Given, u = 0, a = 1m/s2, from equation (1) we get Sn = (2n-1)/2 ……. (2)

With various values of n, we get Sn

 

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Similar Questions for you

According to question, we can write

 10 = 1 2 a t 2 . . . . . . . . . . . . . . . ( 1 ) a n d                        

1 0 + x = 1 2 a ( 2 t ) 2 . . . . . . . . . . . . . . . . ( 2 )  

X = 1 2 A [ ( 2 t ) 2 t 2 ] = 3 ( 1 2 a t 2 ) = 3 0 m  

 

Average speed = 4 v 2 3 v

= 4 v 3

(d) Initial velocity  = - v j ˆ

Final velocity = v i ˆ

Change in velocity  = v i ˆ - ( - v j ˆ )

= v ( i ˆ + j ˆ ) Momentum gain is along i ˆ + j ˆ

 Force experienced is along i ˆ + j ˆ

  Force experienced is in North-East direction.

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physics ncert solutions class 11th 2023

physics ncert solutions class 11th 2023

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