3.28 The velocity-time graph of a particle in one-dimensional motion is shown in Fig 3.29 :

Which of the following formulae are correct for describing the motion of the particle

over the time-interval t1 to t2:

(a) x(t2 ) = x(t1) + v (t1) (t2 – t1) +(½) a (t2 – t1)2

(b) v(t2 ) = v(t1) + a (t2 – t1)

(c) vaverage = (x(t2) – x(t1))/(t2 – t1)

(d) aaverage = (v(t2) – v(t1))/(t2t1)

(e) x(t2 ) = x(t1) + vaverage (t2 – t1) + (½) aaverage (t2 – t1)2

(f) x(t2 ) – x(t1) = area under the v-t curve bounded by the t-axis and the dotted line

shown.

11 Views|Posted 8 months ago
Asked by Shiksha User
1 Answer
V
8 months ago

3.28 The graph has a non-uniform slope between the intervals t1 and t2 – the graph is not a straight line. The equations (a), (b), and (e) do not describe the motion of the particle. Only the relations (c), (d) and (f) are correct.   

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physics ncert solutions class 11th 2023

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