4.25 An aircraft is flying at a height of 3400 m above the ground. If the angle subtended at a ground observation point by the aircraft positions 10.0 s apart is 30°, what is the speed of the aircraft?

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Vishal Baghel | Contributor-Level 10

9 months ago

4.25

Height of the aircraft from the ground = 3400m

Let A and B be the positions of the aircraft, making an angle of AOB = 30 $°$ . The perpendicular OC and OC is the height of the aircraft. Angles AOC = angle BOC = 15 $°$

In AOC, AC = OC $\tan$
$15 °$ = 3400 $\tan ? 15 °$ = 911.03m

AB = AC + CB = 2AC = 1822m

The distance of AB is cove

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