4.29 A bullet fired at an angle of 30° with the horizontal hits the ground 3.0 km away. By adjusting its angle of projection, can one hope to hit a target 5.0 km away? Assume the muzzle speed to be fixed, and neglect air resistance.

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8 months ago

4.29 The angle of projectile θ = 30 °

The bullet hits the ground at a distance of 3 km, Range R = 3 km

We know horizontal range for a projectile motion, R = u2 sin2 θ / g

3 = u2 sin60 ° / g

u2g = 3/ sin60 ° = 3.464 …………… (1)

To hit a target at 5 km,

Max Range,  Rmax = u2g …………. (2)

On comparing equation (1) and (2), we get

Rmax 

...Read more

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physics ncert solutions class 11th 2023

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