5.21 A stone of mass 0.25 kg tied to the end of a string is whirled round in a circle of radius 1.5 m with a speed of 40 rev./min in a horizontal plane. What is the tension in the string ? What is the maximum speed with which the stone can be whirled around if the string can withstand a maximum tension of 200 N ?

11 Views | Posted 4 months ago

Asked by Shiksha User

1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

4 months ago

Mass of the stone, m = 0.25 kg

Radius of the circular path = 1.5 m

Speed = 40 rev/min = 0.67 rev/s

Angular velocity, $?$ = 2 $? n$ = 2 $* \frac{22}{7} * 0.67$ = 4.19 rev/s

The tension of the string, T = m $?^{2}$ r = 0.25 $* {4.19}^{2} * 1.5$ = 6.59 N

Maximum tension of the string, $T_{m a x}$ = 200 N

From the equation $T_{m a x}$ = ${m v}_{m a x}^{2}$ /r, $v_{m a x}^{2}$ = $T_{m a x} * r / m$

$v_{m a x}^{2}$ = 200 $* 1.5$ /0.25

$v_{m a x}$ = 34.64 m/s

0 Upvotes 0 Downvotes

Similar Questions for you

A block rests on an inclined plane making an angle of 30° with the horizontal. The coefficient of static friction between block and the plane is 0.8. If the frictional force on the block is 10 N, then mass of block (in kg) (Take g = 10 m/s² )

alok kumar singh

Bullets of 0.03 kg mass each hit a plate at a rate of 200 bullets per second with velocity of 50 m/s and reflect back with velocity of 30 m/s. The average force acting on the plate in newton is

alok kumar singh