5.29 Ten one-rupee coins are put on top of each other on a table. Each coin has a mass m. Give the magnitude and direction of

(a) The force on the 7th coin (counted from the bottom) due to all the coins on its top

(b) The force on the 7th coin by the eighth coin

(c) The reaction of the 6th coin on the 7th coin

0 57 Views | Posted 4 months ago
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    Answered by

    Vishal Baghel | Contributor-Level 10

    4 months ago

    (a) The force on the 7th coin is due to the 3 coins kept above it

    The weight of the 3 coins = 3m

    Force exerted on the 7th coin is (3mg) N and the force is acting vertically downwards

    (b) The force on the 7th coin by the 8th coin will be the force exerted by the 3 coins above it = (3mg) N, acting downwards

    (c) The 6th coin will experience the force of 4 coins above it, acting downwards = 4mg

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= 0.92 * 1260 = 1161 m/s

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For 2 kg block

T – 2g sin37 = 2a        . (i)

For 4 kg block

4g – 2T =  4 a 2

2g – T = a                    . (ii)

T = (2g – a)

2g – a – 2g ×  3 5  = 2a

3a = 2g ×  2 5

a = 4 g 1 5

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a = ( m 1 m 2 ) g ( m 1 + m 2 ) = g 8

8m1 – 8m2 = m1 + m2

7m1 = 9m2

m 1 m 2 = 9 7          

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