5.5 A constant retarding force of 50 N is applied to a body of mass 20 kg moving initially with a speed of 15 m s-1. How long does the body take to stop?
5.5 A constant retarding force of 50 N is applied to a body of mass 20 kg moving initially with a speed of 15 m s-1. How long does the body take to stop?
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1 Answer
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The retarding force, F = 50N, the mass m = 20 kg
From the equation F = ma, we get acceleration a = 50 / 20 m/s2 = 2.5 m/s2
The initial speed, u = 15 m/s, the final speed v =0, from the relation v = u-at, we get
T = u/a = 15/2.5 s = 6s
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